1. The problem asks us to interpret and find the value of $C(6)$ given a table of vehicle age in years and corresponding values in thousands. 2. From the table, $C(t)$ represents the value (in thousands) of a vehicle that is $t$ years old. 3. To find $C(6)$, we need to estimate the value of the vehicle at 6 years old using the given data points for ages 0 to 5. 4. The values decrease as age increases, suggesting a linear or near-linear depreciation. 5. Using the points for ages 5 and 4: $$C(5) = 11.4, \quad C(4) = 13.5$$ 6. Calculate the slope $m$ between these points: $$m = \frac{C(5) - C(4)}{5 - 4} = \frac{11.4 - 13.5}{1} = -2.1$$ 7. Use the point-slope form to estimate $C(6)$: $$C(6) = C(5) + m \times (6 - 5) = 11.4 + (-2.1) \times 1 = 11.4 - 2.1 = 9.3$$ 8. Interpretation: $C(6)$ means the estimated value (in thousands) of the vehicle when it is 6 years old. 9. Final answer: $$\boxed{C(6) = 9.3}$$ This means the vehicle is worth approximately 9.3 thousand at 6 years old.