Question: Grade 10 Math Unit 4 - Quadratic Relations Assessment-July 2026
Question 3 (2 points)
The vertex of a quadratic relation is (6, -4) and the value of a is 3. Determine the equation in vertex form.
1. **State the problem:** We are given the vertex of a quadratic relation as $ (6, -4) $ and the value of $ a = 3 $. We need to find the equation in vertex form.
2. **Recall the vertex form of a quadratic equation:**
$$ y = a(x - h)^2 + k $$
where $ (h, k) $ is the vertex.
3. **Substitute the given values:**
- $ h = 6 $
- $ k = -4 $
- $ a = 3 $
So,
$$ y = 3(x - 6)^2 - 4 $$
4. **Interpretation:** The vertex form shows the parabola opens upwards (since $ a = 3 > 0 $) and is shifted right by 6 units and down by 4 units.
5. **Answer:** The correct equation is
$$ y = 3(x - 6)^2 - 4 $$