1. **State the problem:** We are given a function with vertical asymptotes at $x = -3$ and $x = 2$. We want to find a possible expression for the function $y$ that matches these characteristics. 2. **Recall the formula for vertical asymptotes:** Vertical asymptotes occur where the denominator of a rational function is zero and the numerator is nonzero. If the asymptotes are at $x = -3$ and $x = 2$, the denominator must have factors $(x + 3)$ and $(x - 2)$. 3. **Form the denominator:** The denominator is $(x + 3)(x - 2)$ or possibly powers of these factors if multiplicity is greater than 1. 4. **Consider the behavior near asymptotes:** Since the function tends to positive or negative infinity near these lines, the factors likely appear in the denominator with multiplicity 1. 5. **Choose a numerator:** To keep it simple, choose numerator as a constant, say 1. 6. **Write the function:** $$y = \frac{1}{(x + 3)(x - 2)}$$ 7. **Check the vertical asymptotes:** At $x = -3$, denominator is zero, so vertical asymptote. At $x = 2$, denominator is zero, so vertical asymptote. This matches the problem description. **Final answer:** $$y = \frac{1}{(x + 3)(x - 2)}$$