1. The problem states that we have a vertical line defined by the equation $x=5$. 2. This line represents all points in the coordinate plane where the $x$-coordinate is exactly 5. 3. Points to the left of this line have $x$-values less than 5. 4. Given points S and Q lie to the left of the line $x=5$, so their $x$-coordinates satisfy $x < 5$. 5. This means for any point $P(x,y)$ to be left of the line $x=5$, the condition is $x < 5$. 6. The line $x=5$ itself is vertical and passes through all points where $x=5$ regardless of $y$. 7. This vertical line divides the plane into two halves: left side where $x<5$ and right side where $x>5$. Final answer: Points S and Q have $x$-coordinates less than 5, meaning they lie to the left of the vertical line $x=5$.