1. **Problem Statement:** Find the volume $V$ when $V = \frac{1}{3}Ah$, $A = 43$, and $h = 6$. 2. **Formula:** The volume of a pyramid or cone is given by $$V = \frac{1}{3} A h$$ where $A$ is the area of the base and $h$ is the height. 3. **Substitute values:** $$V = \frac{1}{3} \times 43 \times 6$$ 4. **Calculate:** $$V = \frac{1}{3} \times 258$$ 5. **Simplify:** $$V = \cancel{\frac{1}{3}} \times \cancel{258} = 86$$ 6. **Answer:** The volume $V$ is **86**. This completes the solution for the first problem.