Subjects algebra

Ward Turnover Share 50864E

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1. **State the problem:** We have a hospital with two wards, A and B. Ward A has 40% of the beds and contributes 60% of the total turnover of 120 million. Ward B has the remaining 60% of beds and 40% of turnover. 2. **Given data:** - Total beds: 100% (Ward A: 40%, Ward B: 60%) - Total turnover: 120 million - Ward A turnover: 60% of 120 million = $0.6 \times 120 = 72$ million - Ward B turnover: 40% of 120 million = $0.4 \times 120 = 48$ million 3. **Turnover per bed before change:** - Ward A turnover per bed = $\frac{72}{40} = 1.8$ million per bed - Ward B turnover per bed = $\frac{48}{60} = 0.8$ million per bed 4. **Change in bed capacity:** - Ward B beds increase by 20% of its previous capacity: $60 \times 1.2 = 72$ beds - Total beds remain the same, so Ward A beds decrease by the increase in Ward B beds: $$40 - (72 - 60) = 40 - 12 = 28$$ beds 5. **Turnover per bed remains unchanged, so new turnovers:** - Ward A new turnover = $28 \times 1.8 = 50.4$ million - Ward B new turnover = $72 \times 0.8 = 57.6$ million 6. **Total turnover after change:** $$50.4 + 57.6 = 108$$ million (Note: total turnover decreased because beds decreased in Ward A) 7. **Share of Ward A in total turnover after change:** $$\frac{50.4}{108} = 0.4667 = 46.7\%$$ **Final answer:** Ward A's share in total turnover after the change is **46.7%**.