1. **State the problem:** We know that 730 ml of water is needed for 900 grams of flour. We want to find out how much water is needed for 1000 grams of flour. 2. **Set up the proportion:** Since the amount of water is proportional to the amount of flour, we use the formula: $$\frac{\text{water}_1}{\text{flour}_1} = \frac{\text{water}_2}{\text{flour}_2}$$ where $\text{water}_1 = 730$ ml, $\text{flour}_1 = 900$ g, $\text{flour}_2 = 1000$ g, and $\text{water}_2$ is what we want to find. 3. **Plug in the known values:** $$\frac{730}{900} = \frac{\text{water}_2}{1000}$$ 4. **Solve for $\text{water}_2$ by cross-multiplying:** $$730 \times 1000 = 900 \times \text{water}_2$$ 5. **Isolate $\text{water}_2$:** $$\text{water}_2 = \frac{730 \times 1000}{900}$$ 6. **Simplify the fraction by canceling common factors:** $$\text{water}_2 = \frac{\cancel{730} \times 1000}{\cancel{900}} = \frac{730000}{900}$$ 7. **Calculate the value:** $$\text{water}_2 = 811.11 \text{ ml (rounded to two decimal places)}$$ **Final answer:** For 1000 grams of flour, you need approximately 811.11 ml of water.