1. **Stating the problem:** We have two taps flowing simultaneously. One tap flows at 10 milliliters per second, the other at 5 milliliters per second. 2. **Identify which graph corresponds to which tap:** The amount of water $a$ in milliliters after $t$ seconds is given by the linear function $a = rt$, where $r$ is the flow rate in milliliters per second. 3. **Analyze the graphs:** - Graph A passes through points $(0,0)$ and $(6,10)$. - Graph B passes through points $(0,0)$ and $(6,5)$. Calculate the slope (rate) for each graph: $$\text{slope}_A = \frac{10 - 0}{6 - 0} = \frac{10}{6} = \frac{5}{3} \approx 1.67$$ $$\text{slope}_B = \frac{5 - 0}{6 - 0} = \frac{5}{6} \approx 0.83$$ 4. **Compare slopes with flow rates:** - Tap 1 flow rate: 10 ml/s - Tap 2 flow rate: 5 ml/s Since the graph slopes are much smaller than the actual flow rates, the graph's vertical scale must be adjusted. 5. **Adjust vertical axis scale:** Given that after 6 seconds, graph A shows 10 units and graph B shows 5 units, the vertical axis units correspond directly to milliliters. 6. **Conclusion:** - Graph A corresponds to the tap with 10 ml/s flow rate. - Graph B corresponds to the tap with 5 ml/s flow rate. 7. **Answer to part b:** The vertical axis should be labeled with values matching the water amount in milliliters, e.g., 0, 2, 4, 6, 8, 10, etc., to reflect the actual water volume. **Final answers:** - a) Graph A shows water flow from the first tap (10 ml/s), Graph B shows water flow from the second tap (5 ml/s). - b) The vertical axis scale should be marked in increments of 2 milliliters to accurately represent water volume.