1. **State the problem:** A bucket initially contains 25 litres of water. It loses 12% of its water every minute due to a leak. We need to find the amount of water left after 10 minutes using the concept of compound decay.
2. **Formula used:** The amount remaining after compound decay is given by:
$$ A = P \times (1 - r)^t $$
where:
- $A$ is the amount after time $t$,
- $P$ is the initial amount,
- $r$ is the decay rate per time period (as a decimal),
- $t$ is the number of time periods.
3. **Identify values:**
- $P = 25$ litres
- $r = 0.12$ (12% loss per minute)
- $t = 10$ minutes
4. **Calculate:**
$$ A = 25 \times (1 - 0.12)^{10} = 25 \times (0.88)^{10} $$
5. **Evaluate:**
Calculate $0.88^{10}$:
$$ 0.88^{10} \approx 0.2785 $$
6. **Final amount:**
$$ A = 25 \times 0.2785 = 6.9625 $$ litres
**Answer:** After 10 minutes, approximately **6.96 litres** of water remain in the bucket.
Water Leak Decay 9D4E09
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