Subjects algebra

Weight Fuel 44F2Ac

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1. **State the problem:** We have the linear function $$W = 6F + 4000$$ where $W$ is the weight of the airplane in pounds and $F$ is the amount of fuel in gallons. 2. **Identify domain and range:** The domain is the set of all possible values for $F$, the amount of fuel in gallons. Since the fuel tank can hold from 0 to 300 gallons, the domain is $$0 \leq F \leq 300$$. 3. **Calculate the range:** To find the range, substitute the domain endpoints into the function. - When $F=0$, $$W = 6(0) + 4000 = 4000$$ pounds. - When $F=300$, $$W = 6(300) + 4000 = 1800 + 4000 = 5800$$ pounds. 4. **Interpretation:** The range is the set of possible weights of the airplane, which varies from 4000 pounds (empty fuel) to 5800 pounds (full tank). 5. **Summary:** - Domain: amount of fuel in gallons, $$0 \leq F \leq 300$$ - Range: weight of airplane in pounds, $$4000 \leq W \leq 5800$$