1. **State the problem:** Find the x-intercept(s) of the function $$f(x) = \frac{x+2}{x^2 - 4}$$. 2. **Recall the rule for x-intercepts:** The x-intercept(s) occur where the function crosses the x-axis, which means $$f(x) = 0$$. For a rational function $$\frac{N(x)}{D(x)}$$, this happens when the numerator $$N(x) = 0$$ and the denominator $$D(x) \neq 0$$. 3. **Set the numerator equal to zero:** $$x + 2 = 0$$ $$x = -2$$ 4. **Check the denominator at $$x = -2$$:** $$x^2 - 4 = (-2)^2 - 4 = 4 - 4 = 0$$ Since the denominator is zero at $$x = -2$$, the function is undefined there, so $$x = -2$$ is not an x-intercept. 5. **Check other options:** - For $$x = 2$$, numerator: $$2 + 2 = 4 \neq 0$$, so not an x-intercept. - For $$x = 0$$, numerator: $$0 + 2 = 2 \neq 0$$, so not an x-intercept. 6. **Conclusion:** There are no x-intercepts because the only zero of the numerator is also a zero of the denominator, making the function undefined there. **Final answer:** d) none