1. **State the problem:** Find the x-intercept of the function $$f(x) = \frac{x + 2}{x^2 - 4}$$. 2. **Recall the rule for x-intercepts:** The x-intercept occurs where the function crosses the x-axis, which means $$f(x) = 0$$. For a rational function, this happens when the numerator is zero (and the denominator is not zero). 3. **Set the numerator equal to zero:** $$x + 2 = 0$$ 4. **Solve for x:** $$x = -2$$ 5. **Check the denominator at $$x = -2$$:** $$x^2 - 4 = (-2)^2 - 4 = 4 - 4 = 0$$ Since the denominator is zero at $$x = -2$$, the function is undefined there, so $$x = -2$$ is not in the domain and cannot be an x-intercept. 6. **Check for other zeros of the numerator:** The numerator is linear and only zero at $$x = -2$$, so no other zeros. 7. **Conclusion:** There is no x-intercept because the only zero of the numerator is also a zero of the denominator, causing a vertical asymptote, not an x-intercept. **Final answer:** d) none