1. **State the problem:** Find the x- and y-intercepts of the line given by the equation $x + 10y = 20$. 2. **Recall the intercept rules:** - The x-intercept occurs where $y=0$. - The y-intercept occurs where $x=0$. 3. **Find the x-intercept:** Set $y=0$ in the equation: $$x + 10(0) = 20 \implies x = 20$$ So, the x-intercept is at the point $(20, 0)$. 4. **Find the y-intercept:** Set $x=0$ in the equation: $$0 + 10y = 20 \implies 10y = 20 \implies y = \frac{20}{10} = 2$$ So, the y-intercept is at the point $(0, 2)$. 5. **Final answer:** - x-intercept: $20$ - y-intercept: $2$