1. The problem asks for the y-intercept of the line given by the equation $$y + 15 = 12 - 2x$$. 2. The y-intercept is the point where the line crosses the y-axis. At this point, the value of $x$ is 0. 3. To find the y-intercept, substitute $x = 0$ into the equation: $$y + 15 = 12 - 2(0)$$ 4. Simplify the right side: $$y + 15 = 12$$ 5. Solve for $y$ by subtracting 15 from both sides: $$y + \cancel{15} - \cancel{15} = 12 - 15$$ $$y = -3$$ 6. Therefore, the y-intercept is the point where $x=0$ and $y=-3$, or $(0, -3)$. This means the line crosses the y-axis at $-3$.