1. The problem is to find the y-intercept of the function $$y = \frac{9x - 36}{3x + 3}$$. 2. The y-intercept occurs where $$x = 0$$. To find it, substitute $$x = 0$$ into the function. 3. Substitute $$x = 0$$: $$y = \frac{9(0) - 36}{3(0) + 3} = \frac{0 - 36}{0 + 3} = \frac{-36}{3}$$ 4. Simplify the fraction: $$y = \frac{\cancel{-36}}{\cancel{3}} = -12$$ 5. Therefore, the y-intercept is at the point $$(0, -12)$$. This means the graph crosses the y-axis at $$-12$$.