Subjects algebra

Zero Exponent Df56D0

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1. **State the problem:** Simplify the expression $8 \times (4t)^0$. 2. **Recall the rule:** Any nonzero number or expression raised to the power of zero equals 1. That is, for any $x \neq 0$, $x^0 = 1$. 3. **Apply the rule:** Since $(4t)^0 = 1$ (assuming $t$ is not zero), the expression becomes: $$8 \times 1 = 8$$ 4. **Final answer:** The simplified expression is $8$. This simplification works because the zero exponent rule applies regardless of the base, as long as it is not zero.