1. **State the problem:** Add the two 3-digit numbers given in each problem. 2. **Formula used:** Addition of multi-digit numbers is done by adding digits column-wise from right (ones) to left (hundreds), carrying over if the sum exceeds 9. 3. **Step-by-step addition for problem (1):** - Add ones: $0 + 9 = 9$ - Add tens: $6 + 7 = 13$, write 3 and carry 1 - Add hundreds: $1 + 0 + 1 (carry) = 2$ - Final sum: $239$ 4. **Step-by-step addition for problem (2):** - Ones: $6 + 9 = 15$, write 5 carry 1 - Tens: $6 + 7 + 1 = 14$, write 4 carry 1 - Hundreds: $2 + 0 + 1 = 3$ - Final sum: $345$ 5. **Step-by-step addition for problem (3):** - Ones: $7 + 9 = 16$, write 6 carry 1 - Tens: $6 + 5 + 1 = 12$, write 2 carry 1 - Hundreds: $2 + 0 + 1 = 3$ - Final sum: $326$ 6. **Step-by-step addition for problem (4):** - Ones: $4 + 9 = 13$, write 3 carry 1 - Tens: $6 + 5 + 1 = 12$, write 2 carry 1 - Hundreds: $3 + 0 + 1 = 4$ - Final sum: $423$ 7. **Step-by-step addition for problem (5):** - Ones: $5 + 8 = 13$, write 3 carry 1 - Tens: $7 + 5 + 1 = 13$, write 3 carry 1 - Hundreds: $2 + 0 + 1 = 3$ - Final sum: $333$ 8. **Step-by-step addition for problem (6):** - Ones: $4 + 8 = 12$, write 2 carry 1 - Tens: $7 + 9 + 1 = 17$, write 7 carry 1 - Hundreds: $2 + 0 + 1 = 3$ - Final sum: $372$ 9. **Step-by-step addition for problem (7):** - Ones: $9 + 3 = 12$, write 2 carry 1 - Tens: $8 + 9 + 1 = 18$, write 8 carry 1 - Hundreds: $3 + 0 + 1 = 4$ - Final sum: $482$ 10. **Step-by-step addition for problem (8):** - Ones: $9 + 3 = 12$, write 2 carry 1 - Tens: $5 + 4 + 1 = 10$, write 0 carry 1 - Hundreds: $4 + 0 + 1 = 5$ - Final sum: $502$ **Final answers:** (1) 239 (2) 345 (3) 326 (4) 423 (5) 333 (6) 372 (7) 482 (8) 502 This method ensures correct addition by place value and carrying over when sums exceed 9.