1. The problem asks for the ratio of Toyin's age to Ade's age. 2. Toyin is 16 years old and Ade is 12 years old. 3. The ratio is therefore $$\frac{16}{12}$$. 4. Simplify the fraction by dividing numerator and denominator by 4: $$\frac{16 \div 4}{12 \div 4} = \frac{4}{3}$$. 5. So, the ratio of Toyin's age to Ade's age is **4:3**. --- 1. Find the ratio of Tola's height to Funmilola's height. 2. Tola's height is 1.10 m and Funmilola's is 1.25 m. 3. The ratio is $$\frac{1.10}{1.25}$$. 4. Convert to fractions or decimals: $$\frac{1.10}{1.25} = \frac{110}{125}$$. 5. Simplify by dividing numerator and denominator by 5: $$\frac{110 \div 5}{125 \div 5} = \frac{22}{25}$$. 6. So, the ratio of Tola's height to Funmilola's height is **22:25**. --- 1. A bag has 40 oranges, 15 of which are bad. 2. The good oranges = 40 - 15 = 25. 3. We want the ratio of bad oranges to good oranges: $$\frac{15}{25}$$. 4. Simplify by dividing numerator and denominator by 5: $$\frac{15 \div 5}{25 \div 5} = \frac{3}{5}$$. 5. The ratio of bad to good oranges is **3:5**. --- 1. Find the ratio of 12 m to 15 m. 2. The ratio is $$\frac{12}{15}$$. 3. Simplify by dividing numerator and denominator by 3: $$\frac{12 \div 3}{15 \div 3} = \frac{4}{5}$$. 4. So, the ratio is **4:5**. --- 1. The ratio of boys to girls is 5 : 8. 2. There are 25 boys. 3. Let the number of girls be $$x$$. 4. Set up the proportion: $$\frac{5}{8} = \frac{25}{x}$$. 5. Cross multiply: $$5x = 8 \times 25$$ $$5x = 200$$ 6. Divide both sides by 5: $$x = \frac{200}{5} = 40$$. 7. So, there are **40 girls** in the class.