1. **State the problem:** A baker needs 5 lb of butter. She has two portions each weighing $1 \frac{1}{6}$ lb and one portion weighing $2 \frac{2}{7}$ lb. We need to check if the total butter is at least 5 lb. 2. **Convert mixed numbers to improper fractions:** - $1 \frac{1}{6} = \frac{7}{6}$ - $2 \frac{2}{7} = \frac{16}{7}$ 3. **Calculate total butter weight:** - Two portions of $\frac{7}{6}$ lb each: $2 \times \frac{7}{6} = \frac{14}{6}$ - Add the third portion: $\frac{14}{6} + \frac{16}{7}$ 4. **Find common denominator and add:** - Common denominator of 6 and 7 is 42. - Convert fractions: $\frac{14}{6} = \frac{14 \times 7}{6 \times 7} = \frac{98}{42}$ - $\frac{16}{7} = \frac{16 \times 6}{7 \times 6} = \frac{96}{42}$ - Sum: $\frac{98}{42} + \frac{96}{42} = \frac{194}{42}$ 5. **Simplify the fraction:** - $\frac{194}{42} = \frac{\cancel{2} \times 97}{\cancel{2} \times 21} = \frac{97}{21}$ 6. **Convert back to mixed number:** - $\frac{97}{21} = 4 \frac{13}{21}$ (since $21 \times 4 = 84$, remainder 13) 7. **Compare to required 5 lb:** - $4 \frac{13}{21} < 5$ **Conclusion:** The baker does not have enough butter for the recipe.