Candy Bars 807052

Let's solve this candy problem step by step! 🍬🍫 1. Imagine Dawn has $x$ candy bars in total. 2. She puts 28% in Bag A, so Bag A has $0.28x$ candy bars. 3. The rest go to Bag B, so Bag B has $x - 0.28x = 0.72x$ candy bars. 4. Then, Dawn moves 110 candy bars from Bag B to Bag A. 5. After moving, Bag A has $0.28x + 110$ candy bars. 6. Bag B now has $0.72x - 110$ candy bars. 7. The problem says both bags have the same number of candy bars now, so: $$0.28x + 110 = 0.72x - 110$$ 8. Let's solve this equation: **Step 1:** Move $0.28x$ to the right and $110$ to the left: $$110 + 110 = 0.72x - 0.28x$$ $$220 = 0.44x$$ **Step 2:** Divide both sides by $0.44$: $$x = \frac{220}{0.44} = 500$$ 9. So, Dawn had 500 candy bars in total. 10. Now, find how many candy bars are in each bag at the end: Bag A: $$0.28 \times 500 + 110 = 140 + 110 = 250$$ Bag B: $$0.72 \times 500 - 110 = 360 - 110 = 250$$ **Great! Both bags have 250 candy bars each at the end.** 🎉 **Visual:** ➕ 110 candy bars moved ➡️ + ➖ 110 candy bars moved ➡️ 🎯 Final answer: Each bag has 250 candy bars! Great job! You solved it! 🎉