1. **State the problem:** We need to create a decimal number that ends in the thousandths place, has a 2 in the thousandths place, and rounds to 2 when rounded to the nearest whole number.
2. **Understand the rounding rule:** When rounding to the nearest whole number, if the decimal part is 0.5 or greater, round up; if less than 0.5, round down.
3. **Analyze the requirements:**
- The number ends in the thousandths place, so it has three decimal digits.
- The digit in the thousandths place is 2.
- When rounded to the nearest whole number, the result is 2.
4. **Construct the number:**
- The whole number part must be 2 because rounding to 2 means the number is close to 2.
- The decimal part must be less than 0.5 to round down to 2.
- The thousandths digit is 2, so the decimal part looks like 0.00x where x=2.
5. **Example number:**
$$2.002$$
6. **Verify rounding:**
- Rounding 2.002 to the nearest whole number:
$$\text{Since } 0.002 < 0.5, \text{round down to } 2.$$
7. **Final answer:**
The number is **2.002** which ends in the thousandths place, has a 2 in the thousandths place, and rounds to 2 when rounded to the nearest whole number.
Decimal Rounding 3C35Dd
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