1. The problem is to perform division of a 3-digit number by a 2-digit number with no remainders. 2. Let's solve the first division: $672 \div 42$. 3. The formula for division is: $$\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}$$ 4. Here, Dividend = 672, Divisor = 42. 5. We want to find Quotient such that Remainder = 0. 6. Calculate: $$672 \div 42 = ?$$ 7. Try multiplying 42 by numbers close to $\frac{672}{42} = 16$: $$42 \times 16 = 672$$ 8. Since $42 \times 16 = 672$, the quotient is 16 and remainder is 0. 9. So, the division is: $$672 \div 42 = 16$$ 10. This matches the long division steps shown. Final answer: $16$