Subjects arithmetic

Division With Remainder 5E451D

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1. The problem is to divide 85 by 4 and find the quotient and remainder. 2. The division formula is: $$\text{Dividend} = (\text{Divisor} \times \text{Quotient}) + \text{Remainder}$$ 3. Start dividing 85 by 4 using long division: - Divide the tens place: 8 tens divided by 4 is 2 tens (since $4 \times 2 = 8$). - Write 2 in the quotient's tens place. - Subtract $8$ (which is $4 \times 2$) from 8 tens (80), remainder is 0 tens. 4. Bring down the ones digit 5: - Now divide 5 by 4. - 4 goes into 5 once (1), so write 1 in the quotient's ones place. - Subtract $4 \times 1 = 4$ from 5, remainder is 1. 5. So the quotient is $21$ and the remainder is $1$. 6. Check the work: $$85 = (4 \times 21) + 1 = 84 + 1 = 85$$ This confirms the division is correct. Final answer: - Quotient = 21 - Remainder = 1