Subjects arithmetic

Division With Remainder F11A11

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1. **State the problem:** Divide 209 by 11 and find the quotient and remainder. 2. **Formula and rules:** When dividing integers, the division algorithm states: $$a = bq + r$$ where $a$ is the dividend, $b$ is the divisor, $q$ is the quotient, and $r$ is the remainder with $0 \leq r < b$. 3. **Perform the division:** Divide 209 by 11: $$209 \div 11 = ?$$ 4. **Calculate the quotient:** Find the largest integer $q$ such that $11q \leq 209$. Since $11 \times 19 = 209$, we have: $$q = 19$$ 5. **Calculate the remainder:** $$r = 209 - 11 \times 19 = 209 - 209 = 0$$ 6. **Conclusion:** The quotient is 19 and the remainder is 0. **Final answer:** $$209 \div 11 = 19 \text{ R } 0$$