1. **State the problem:** Harry caught two fish. The first fish weighs 39 lb 12 oz, and the second fish weighs 24 lb 9 oz. We need to find how much more the first fish weighs than the second. 2. **Formula:** To find how much more one quantity is than another, subtract the smaller weight from the larger weight: $$\text{Difference} = \text{Weight of first fish} - \text{Weight of second fish}$$ 3. **Convert weights to a consistent unit:** Since weights are given in pounds (lb) and ounces (oz), and 1 lb = 16 oz, convert both weights entirely to ounces for easier subtraction. - First fish: $$39 \text{ lb } 12 \text{ oz} = 39 \times 16 + 12 = 624 + 12 = 636 \text{ oz}$$ - Second fish: $$24 \text{ lb } 9 \text{ oz} = 24 \times 16 + 9 = 384 + 9 = 393 \text{ oz}$$ 4. **Subtract the weights in ounces:** $$636 - 393 = 243 \text{ oz}$$ 5. **Convert the difference back to pounds and ounces:** Divide 243 oz by 16 to find pounds: $$243 \div 16 = 15 \text{ remainder } 3$$ So, the difference is 15 lb 3 oz. 6. **Answer:** The first fish weighs 15 lb 3 oz more than the second fish.