1. **Stating the problem:** We are given three sets of numbers (Math 1, Math 2, Math 3) and asked to solve or simplify them. 2. **Math 1: Convert mixed numbers to improper fractions** - $3 \frac{2}{5} = \frac{3 \times 5 + 2}{5} = \frac{15 + 2}{5} = \frac{17}{5}$ - $-6 \frac{3}{7} = -\frac{6 \times 7 + 3}{7} = -\frac{42 + 3}{7} = -\frac{45}{7}$ - $1 \frac{4}{5} = \frac{1 \times 5 + 4}{5} = \frac{5 + 4}{5} = \frac{9}{5}$ 3. **Math 2: Simplify fractions** - $\frac{17}{3}$ is already simplified. - $-\frac{21}{3} = -\cancel{\frac{21}{3}} = -7$ (since $21 \div 3 = 7$) - $-\frac{19}{10}$ is already simplified. 4. **Math 3: Convert mixed fraction and simplify fractions** - $\frac{3}{10}$ is already simplified. - $\frac{1}{2}$ is already simplified. - $\frac{1}{4}$ is already simplified. - $1 \frac{2}{3} = \frac{1 \times 3 + 2}{3} = \frac{3 + 2}{3} = \frac{5}{3}$ **Final answers:** - Math 1: $\frac{17}{5}$, $-\frac{45}{7}$, $\frac{9}{5}$ - Math 2: $\frac{17}{3}$, $-7$, $-\frac{19}{10}$ - Math 3: $\frac{3}{10}$, $\frac{1}{2}$, $\frac{1}{4}$, $\frac{5}{3}$