Subjects arithmetic

Fraction Operations 0538A9

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Question: (3) -1 2/3 + 1/15 = -1 10/15 + 1/15 (4) -1 2/3 - 1/15 = -1 10/15 - 1/15 (5) - 2/3 + 2 1/15 = (6) 2/3 - 2 1/15 =User:
1. **Problem:** Simplify and verify the equality for (3) $-1 \frac{2}{3} + \frac{1}{15} = -1 \frac{10}{15} + \frac{1}{15}$. 2. Convert mixed numbers to improper fractions: $$-1 \frac{2}{3} = -\left(1 + \frac{2}{3}\right) = -\frac{5}{3}$$ $$-1 \frac{10}{15} = -\left(1 + \frac{10}{15}\right) = -\frac{25}{15}$$ 3. Express all fractions with a common denominator 15: $$-\frac{5}{3} = -\frac{5 \times 5}{3 \times 5} = -\frac{25}{15}$$ 4. Substitute back: $$-\frac{25}{15} + \frac{1}{15} = -\frac{25}{15} + \frac{1}{15}$$ 5. Add the fractions: $$-\frac{25}{15} + \frac{1}{15} = -\frac{24}{15}$$ 6. Simplify the fraction by dividing numerator and denominator by 3: $$-\frac{\cancel{24}}{\cancel{15}} = -\frac{8}{5}$$ 7. Similarly, the right side: $$-\frac{25}{15} + \frac{1}{15} = -\frac{24}{15} = -\frac{8}{5}$$ 8. Both sides equal $-\frac{8}{5}$, so the equality holds. --- 1. **Problem:** Simplify and verify the equality for (4) $-1 \frac{2}{3} - \frac{1}{15} = -1 \frac{10}{15} - \frac{1}{15}$. 2. Using previous conversions: $$-1 \frac{2}{3} = -\frac{25}{15}$$ 3. Substitute: $$-\frac{25}{15} - \frac{1}{15} = -\frac{25}{15} - \frac{1}{15}$$ 4. Add the fractions: $$-\frac{25}{15} - \frac{1}{15} = -\frac{26}{15}$$ 5. Right side: $$-1 \frac{10}{15} - \frac{1}{15} = -\frac{25}{15} - \frac{1}{15} = -\frac{26}{15}$$ 6. Both sides equal $-\frac{26}{15}$, so the equality holds. --- 1. **Problem:** Simplify (5) $- \frac{2}{3} + 2 \frac{1}{15}$. 2. Convert mixed number to improper fraction: $$2 \frac{1}{15} = \frac{31}{15}$$ 3. Express $-\frac{2}{3}$ with denominator 15: $$-\frac{2}{3} = -\frac{10}{15}$$ 4. Add: $$-\frac{10}{15} + \frac{31}{15} = \frac{21}{15}$$ 5. Simplify by dividing numerator and denominator by 3: $$\frac{\cancel{21}}{\cancel{15}} = \frac{7}{5}$$ --- 1. **Problem:** Simplify (6) $\frac{2}{3} - 2 \frac{1}{15}$. 2. Convert mixed number: $$2 \frac{1}{15} = \frac{31}{15}$$ 3. Express $\frac{2}{3}$ with denominator 15: $$\frac{2}{3} = \frac{10}{15}$$ 4. Subtract: $$\frac{10}{15} - \frac{31}{15} = -\frac{21}{15}$$ 5. Simplify: $$-\frac{\cancel{21}}{\cancel{15}} = -\frac{7}{5}$$