1. **Problem 15:** A student reads $\frac{3}{8}$ of a book on Monday and $\frac{1}{4}$ on Tuesday. We need to find the fraction of the book that remains unread. 2. The total fraction read is the sum of the fractions read on Monday and Tuesday: $$\frac{3}{8} + \frac{1}{4}$$ 3. Convert $\frac{1}{4}$ to eighths to add easily: $$\frac{1}{4} = \frac{2}{8}$$ 4. Add the fractions: $$\frac{3}{8} + \frac{2}{8} = \frac{5}{8}$$ 5. The fraction unread is the whole book minus the fraction read: $$1 - \frac{5}{8}$$ 6. Convert 1 to eighths: $$\frac{8}{8} - \frac{5}{8}$$ 7. Subtract: $$\frac{8}{8} - \frac{5}{8} = \frac{3}{8}$$ 8. **Answer for Question 15:** The fraction of the book unread is $\frac{3}{8}$. --- 9. **Problem 16:** A bottle contains $\frac{2}{3}$ litre of juice shared equally among 4 children. Find how much juice each child receives. 10. Use the formula for equal sharing: $$\text{Amount per child} = \frac{\text{Total juice}}{\text{Number of children}}$$ 11. Substitute values: $$\frac{2}{3} \div 4$$ 12. Division by 4 is multiplication by its reciprocal: $$\frac{2}{3} \times \frac{1}{4}$$ 13. Multiply numerators and denominators: $$\frac{2 \times 1}{3 \times 4} = \frac{2}{12}$$ 14. Simplify the fraction by dividing numerator and denominator by 2: $$\frac{\cancel{2}}{\cancel{12}} = \frac{1}{6}$$ 15. **Answer for Question 16:** Each child receives $\frac{1}{6}$ litre of juice.