1. **Problem statement:** Find the missing numbers in the subtraction equations involving mixed numbers and fractions. 2. **Recall the subtraction rule:** If $a - x = b$, then $x = a - b$. 3. **Solve each part:** **a)** $3 - \square = 2 \frac{3}{10}$ Convert mixed number to improper fraction: $2 \frac{3}{10} = \frac{23}{10}$ Express 3 as fraction with denominator 10: $3 = \frac{30}{10}$ Find $\square$: $$\square = 3 - 2 \frac{3}{10} = \frac{30}{10} - \frac{23}{10} = \frac{30 - 23}{10} = \frac{7}{10}$$ **b)** $4 - \square = 3 \frac{3}{8}$ Convert mixed number: $3 \frac{3}{8} = \frac{27}{8}$ Express 4 as fraction with denominator 8: $4 = \frac{32}{8}$ Find $\square$: $$\square = 4 - 3 \frac{3}{8} = \frac{32}{8} - \frac{27}{8} = \frac{5}{8}$$ **c)** $\square - \frac{7}{12} = 3 \frac{5}{12}$ Convert mixed number: $3 \frac{5}{12} = \frac{41}{12}$ Find $\square$: $$\square = 3 \frac{5}{12} + \frac{7}{12} = \frac{41}{12} + \frac{7}{12} = \frac{48}{12} = 4$$ **d)** $\square - \frac{5}{12} = 13 \frac{7}{12}$ Convert mixed number: $13 \frac{7}{12} = \frac{163}{12}$ Find $\square$: $$\square = 13 \frac{7}{12} + \frac{5}{12} = \frac{163}{12} + \frac{5}{12} = \frac{168}{12} = 14$$ **Final answers:** - a) $\frac{7}{10}$ - b) $\frac{5}{8}$ - c) $4$ - d) $14$