Question: Question 1 ii is actually $2 \frac{4}{9} \div 4 \frac{2}{3} - \frac{3}{7}$ (both are mixed fractions) - $\frac{3}{7}$
1. **State the problem:** Calculate $2 \frac{4}{9} \div 4 \frac{2}{3} - \frac{3}{7}$.
2. **Convert mixed fractions to improper fractions:**
$$2 \frac{4}{9} = \frac{2 \times 9 + 4}{9} = \frac{18 + 4}{9} = \frac{22}{9}$$
$$4 \frac{2}{3} = \frac{4 \times 3 + 2}{3} = \frac{12 + 2}{3} = \frac{14}{3}$$
3. **Rewrite the expression:**
$$\frac{22}{9} \div \frac{14}{3} - \frac{3}{7}$$
4. **Division of fractions rule:** Dividing by a fraction is the same as multiplying by its reciprocal.
$$\frac{22}{9} \div \frac{14}{3} = \frac{22}{9} \times \frac{3}{14}$$
5. **Multiply the fractions:**
$$\frac{22}{9} \times \frac{3}{14} = \frac{22 \times 3}{9 \times 14} = \frac{66}{126}$$
6. **Simplify the fraction by canceling common factors:**
$$\frac{\cancel{66}^{22 \times 3}}{\cancel{126}^{42 \times 3}} = \frac{22}{42}$$
Further simplify by dividing numerator and denominator by 2:
$$\frac{\cancel{22}^{11 \times 2}}{\cancel{42}^{21 \times 2}} = \frac{11}{21}$$
7. **Now subtract $\frac{3}{7}$:**
Find common denominator for $\frac{11}{21}$ and $\frac{3}{7}$, which is 21.
$$\frac{3}{7} = \frac{3 \times 3}{7 \times 3} = \frac{9}{21}$$
8. **Perform the subtraction:**
$$\frac{11}{21} - \frac{9}{21} = \frac{11 - 9}{21} = \frac{2}{21}$$
**Final answer:**
$$\boxed{\frac{2}{21}}$$