1. Problem 23: Is it possible to walk 2595 miles in 6 months?
2. To find out, we calculate the average miles per day needed.
3. There are about 30 days in a month, so 6 months is $6 \times 30 = 180$ days.
4. Average miles per day = $\frac{2595}{180} \approx 14.42$ miles/day.
5. Walking 14.42 miles every day is challenging but possible for a fit person.
6. Problem 24: Are there more or less than 50,000 seconds in a day?
7. Seconds in a day = $24 \times 60 \times 60 = 86400$ seconds.
8. Since 86400 > 50000, there are more than 50,000 seconds in a day.
9. Problem 25: Area comparison of original and doubled photograph.
10. Original area = $4 \times 5 = 20$ square inches.
11. New dimensions: width = 8, length = 10.
12. New area = $8 \times 10 = 80$ square inches.
13. Ratio of new area to original area = $\frac{80}{20} = 4$.
14. The new photograph's area is 4 times larger.
15. Problem 26: Price changes of a watch.
16. Regular price = 50.
17. Sale price after 10% reduction = $50 - 0.10 \times 50 = 50 - 5 = 45$.
18. Price after 10% increase on sale price = $45 + 0.10 \times 45 = 45 + 4.5 = 49.5$.
19. Current price 49.5 is less than regular price 50.
20. Problem 27a: Find 3-digit palindromic squares.
21. A 3-digit palindrome has form $aba$ (e.g., 121, 131).
22. Check squares of natural numbers from 10 to 31 (since $31^2=961$).
23. Palindromic squares found: 121 ($11^2$), 484 ($22^2$), 676 ($26^2$).
24. Problem 27b: Find 4-digit palindromic cubes.
25. 4-digit numbers range from 1000 to 9999.
26. Cube roots approx from $\sqrt[3]{1000}=10$ to $\sqrt[3]{9999} \approx 21.5$.
27. Check cubes of 10 to 21:
- $10^3=1000$ (not palindrome)
- $11^3=1331$ (palindrome)
- $12^3=1728$ (no)
- $13^3=2197$ (no)
- $14^3=2744$ (no)
- $15^3=3375$ (no)
- $16^3=4096$ (no)
- $17^3=4913$ (no)
- $18^3=5832$ (no)
- $19^3=6859$ (no)
- $20^3=8000$ (no)
- $21^3=9261$ (no)
28. Only 1331 is a 4-digit palindromic cube.
29. Problem 28: Speed of car between palindromic odometer readings.
30. Initial reading: 15951.
31. Next palindromic number after 15951 is 16061.
32. Distance traveled = $16061 - 15951 = 110$ miles.
33. Time = 2 hours.
34. Speed = $\frac{110}{2} = 55$ miles per hour.
Final answers:
- 23: Possible with ~14.42 miles/day.
- 24: More than 50,000 seconds.
- 25: New area 4 times larger.
- 26: Current price less than regular price.
- 27a: Palindromic squares: 121, 484, 676.
- 27b: Palindromic cube: 1331.
- 28: Speed = 55 mph.
Multiple Word Problems B09B29
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