1. The problem asks to find the first 5 multiples and all the factors of 12. 2. **Multiples** of a number are found by multiplying the number by natural numbers (1, 2, 3, ...). 3. **Factors** of a number are the integers that divide the number exactly without leaving a remainder. 4. To find the first 5 multiples of 12, calculate: $$12 \times 1 = 12$$ $$12 \times 2 = 24$$ $$12 \times 3 = 36$$ $$12 \times 4 = 48$$ $$12 \times 5 = 60$$ 5. To find all factors of 12, check all integers from 1 to 12 that divide 12 exactly: - 1 divides 12: $12 \div 1 = 12$ - 2 divides 12: $12 \div 2 = 6$ - 3 divides 12: $12 \div 3 = 4$ - 4 divides 12: $12 \div 4 = 3$ - 6 divides 12: $12 \div 6 = 2$ - 12 divides 12: $12 \div 12 = 1$ 6. Therefore, the factors of 12 are: 1, 2, 3, 4, 6, 12. **Final answers:** - First 5 multiples of 12: 12, 24, 36, 48, 60 - All factors of 12: 1, 2, 3, 4, 6, 12