1. The problem asks which partial products are used to solve $34 \times 52$ using an area model. 2. An area model breaks each number into place values and multiplies each part separately. 3. For $34$, the place values are $30$ and $4$. 4. For $52$, the place values are $50$ and $2$. 5. The partial products are then: $$30 \times 50, \quad 30 \times 2, \quad 4 \times 50, \quad 4 \times 2$$ 6. These correspond to option A. 7. To verify, calculate each: $$30 \times 50 = 1500$$ $$30 \times 2 = 60$$ $$4 \times 50 = 200$$ $$4 \times 2 = 8$$ 8. Add all partial products: $$1500 + 60 + 200 + 8 = 1768$$ 9. Note the handwritten product is $1778$, which suggests a small error in the handwritten calculation, but the correct partial products for the area model are those in option A. 10. Therefore, the answer is A. Explanation: The area model multiplies each digit of one number by each digit of the other number according to place value, which is exactly what option A shows.