1. **Problem statement:** We have four tables showing weights and prices of goods. The task is to find the missing prices for each weight in each table, assuming the price per kilogram is constant within each table. 2. **Formula used:** Price per kilogram $p = \frac{\text{Price}}{\text{Weight}}$. 3. **Step-by-step solution for Table 1:** - Given: Weight 4 kg costs 10, Weight 1 kg costs 2.5, Weight 6 kg costs 15, Weight 10 kg costs 25. - Calculate price per kg using first known pair: $p = \frac{10}{4} = 2.5$. - Check consistency: $\frac{2.5}{1} = 2.5$, $\frac{15}{6} = 2.5$, $\frac{25}{10} = 2.5$. - All prices consistent, so missing prices are already given. 4. **Step-by-step solution for Table 2:** - Given: Weight 6 kg costs 9, Weight 1 kg costs 1.5, Weight 11 kg costs 16.5, Weight 15 kg costs 22.5. - Calculate price per kg: $p = \frac{9}{6} = 1.5$. - Check consistency: $\frac{1.5}{1} = 1.5$, $\frac{16.5}{11} = 1.5$, $\frac{22.5}{15} = 1.5$. - All prices consistent, so missing prices are already given. 5. **Step-by-step solution for Table 3:** - Given: Weight 10 kg costs 8, Weight 1 kg costs 0.8, Weight 3 kg costs 2.4, Weight 0.8 kg costs 0.64. - Calculate price per kg: $p = \frac{8}{10} = 0.8$. - Check consistency: $\frac{0.8}{1} = 0.8$, $\frac{2.4}{3} = 0.8$, $\frac{0.64}{0.8} = 0.8$. - All prices consistent, so missing prices are already given. 6. **Step-by-step solution for Table 4:** - Given: Weight 12 kg costs 3, Weight 1 kg costs 0.25, Weight 5 kg costs 1.25, Weight 7 kg costs 1.75. - Calculate price per kg: $p = \frac{3}{12} = 0.25$. - Check consistency: $\frac{0.25}{1} = 0.25$, $\frac{1.25}{5} = 0.25$, $\frac{1.75}{7} = 0.25$. - All prices consistent, so missing prices are already given. **Final answer:** All missing prices can be found by multiplying the weight by the price per kilogram calculated from the known values in each table. The prices given are consistent and complete for each weight.