**Step 1:** Imagine Mrs Lim has 7 meters of ribbon.
**Step 2:** Each parcel uses 3/5 meter of ribbon.
**Step 3:** Letβs see how many parcels she can tie.
**Step 4:** Divide total ribbon by ribbon per parcel: $$7 \div \frac{3}{5} = 7 \times \frac{5}{3} = \frac{35}{3} = 11 \frac{2}{3}$$ parcels.
She can only tie whole parcels, so she ties 11 parcels.
**Step 5:** Calculate ribbon used for 11 parcels: $$11 \times \frac{3}{5} = \frac{33}{5} = 6 \frac{3}{5}$$ meters.
**Step 6:** Find ribbon left: $$7 - 6 \frac{3}{5} = 7 - 6.6 = 0.4$$ meters.
**Step 7:** So, Mrs Lim has 0.4 meters of ribbon left unused.
Great job! π
Ribbon total:
π π π π π π π
(7 meters)
β
π π π π π π π
(7 meters)
Ribbon per parcel:
π π π
3/5 meter
β‘οΈ
π π π
3/5 meter
Parcels tied:
π π π π π
π π π π π
π π
(11 parcels)
=
π π π π π
π π π π π
π π
(11 parcels)
Ribbon used:
π π π π π π π π π π π
(6 3/5 meters)
β
π π π π π π π π π π π
(6 3/5 meters)
Ribbon left:
π π
(0.4 meters)
π π
(0.4 meters)