Subjects arithmetic

Ribbon Leftover 9204C6

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**Step 1:** Imagine Mrs Lim has 7 meters of ribbon. **Step 2:** Each parcel uses 3/5 meter of ribbon. **Step 3:** Let’s see how many parcels she can tie. **Step 4:** Divide total ribbon by ribbon per parcel: $$7 \div \frac{3}{5} = 7 \times \frac{5}{3} = \frac{35}{3} = 11 \frac{2}{3}$$ parcels. She can only tie whole parcels, so she ties 11 parcels. **Step 5:** Calculate ribbon used for 11 parcels: $$11 \times \frac{3}{5} = \frac{33}{5} = 6 \frac{3}{5}$$ meters. **Step 6:** Find ribbon left: $$7 - 6 \frac{3}{5} = 7 - 6.6 = 0.4$$ meters. **Step 7:** So, Mrs Lim has 0.4 meters of ribbon left unused. Great job! πŸŽ‰
Ribbon total:
πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€
(7 meters)
βž•
Ribbon per parcel:
πŸŽ€ πŸŽ€ πŸŽ€
3/5 meter
➑️
Parcels tied:
πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€
πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€
πŸŽ€ πŸŽ€

(11 parcels)
=
Ribbon used:
πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€ πŸŽ€
(6 3/5 meters)
βž–
Ribbon left:
πŸŽ€ πŸŽ€
(0.4 meters)