1. **State the problem:** Elliott starts with £15.50 and makes two subtractions: first £13, then 60p. We need to find how much money he has left. 2. **Convert money to a consistent unit:** To subtract easily, convert pounds and pence to pence only. - £15.50 = 15 pounds and 50 pence = $15 \times 100 + 50 = 1550$ pence - £13 = $13 \times 100 = 1300$ pence - 60p = 60 pence 3. **Subtract £13 from £15.50:** $$1550 - 1300 = 250$$ pence Convert back to pounds and pence: $$250 \text{ pence} = 2 \text{ pounds } 50 \text{ pence}$$ So after the first subtraction, Elliott has £2.50. 4. **Subtract 60p from £2.50:** Convert £2.50 to pence: $$2 \times 100 + 50 = 250$$ pence Subtract 60p: $$250 - 60 = 190$$ pence Convert back to pounds and pence: $$190 \text{ pence} = 1 \text{ pound } 90 \text{ pence}$$ 5. **Final answer:** Elliott has £1.90 left. This matches the problem's final value. **Summary:** - Start: £15.50 - After subtracting £13: £2.50 - After subtracting 60p: £1.90 Hence, Elliott has **£1.90** left.