1. The problem is to find how to get the numbers 17, 32, 48, 60, and 64 from the sum of 141 using the numbers 1, Thur, and 79. 2. First, clarify the meaning of "Thur"; assuming it is a typo or a placeholder, we will focus on the numbers 1 and 79. 3. The sum given is 141, and we want to see if 17, 32, 48, 60, and 64 can be formed by sums or differences involving 1, 79, and 141. 4. Check if each target number can be expressed as a combination of 1, 79, and 141: - For 17: $17 = 79 - 62$ (but 62 is not given), or $17 = 1 + 16$ (16 not given), so no direct sum. - For 32: $32 = 79 - 47$ (47 not given), no direct sum. - For 48: $48 = 79 - 31$ (31 not given), no direct sum. - For 60: $60 = 79 - 19$ (19 not given), no direct sum. - For 64: $64 = 79 - 15$ (15 not given), no direct sum. 5. Since the problem is unclear, if the goal is to find numbers that sum to 141, check sums: - $17 + 32 + 48 + 60 + 64 = 221$, which is greater than 141. 6. Alternatively, if the question is how to get these numbers from 141 by subtraction: - $141 - 124 = 17$ - $141 - 109 = 32$ - $141 - 93 = 48$ - $141 - 81 = 60$ - $141 - 77 = 64$ 7. Without more context, the best interpretation is that these numbers are differences from 141. Final answer: The numbers 17, 32, 48, 60, and 64 can be obtained by subtracting 124, 109, 93, 81, and 77 respectively from 141.