1. Stating the problem: We need to find the total cost of all items listed for the installation of the shower by summing all individual costs. 2. List all costs: - Tuyuox ppr 12 × 4500 = 54000 - Tuyuox PVC 110 5 × 12000 = 60000 - Tuyuox PVC 63 4 × 9000 = 36000 - Coude PVC 110 4 × 1500 = 6000 - Coude ppr 30 × 500 = 15000 - Coude PVC 63 10 × 1000 = 10000 - Tee 63 5 × 1200 = 6000 - Tee ppr 13 × 600 = 7800 - Tee PVC 110 2 × 1500 = 3000 - Coude adapter 14 × 800 = 11200 - Macho ppr 6 × 500 = 3000 - Colle tanqite 1 × 8000 = 8000 - Coude merranger 2 × 5000 = 10000 - Macho courbe 6 × 1000 = 6000 3. Sum all costs: $$54000 + 60000 + 36000 + 6000 + 15000 + 10000 + 6000 + 7800 + 3000 + 11200 + 3000 + 8000 + 10000 + 6000$$ 4. Calculate step-by-step: $$54000 + 60000 = 114000$$ $$114000 + 36000 = 150000$$ $$150000 + 6000 = 156000$$ $$156000 + 15000 = 171000$$ $$171000 + 10000 = 181000$$ $$181000 + 6000 = 187000$$ $$187000 + 7800 = 194800$$ $$194800 + 3000 = 197800$$ $$197800 + 11200 = 209000$$ $$209000 + 3000 = 212000$$ $$212000 + 8000 = 220000$$ $$220000 + 10000 = 230000$$ $$230000 + 6000 = 236000$$ 5. Final answer: The total cost for the installation materials is **236000**.