1. **State the problem:** A cooler contains $6 \frac{3}{4}$ liters of water. A team drinks $\frac{2}{3}$ of the water. We need to find how many liters the team drinks.
2. **Convert mixed number to improper fraction:**
$$6 \frac{3}{4} = \frac{6 \times 4 + 3}{4} = \frac{24 + 3}{4} = \frac{27}{4}$$
3. **Set up the multiplication to find the amount drunk:**
The team drinks $\frac{2}{3}$ of $\frac{27}{4}$ liters, so:
$$\frac{2}{3} \times \frac{27}{4}$$
4. **Multiply the fractions:**
$$\frac{2 \times 27}{3 \times 4} = \frac{54}{12}$$
5. **Simplify the fraction:**
Divide numerator and denominator by 6:
$$\frac{\cancel{54}^{9}}{\cancel{12}^{2}} = \frac{9}{2}$$
6. **Convert improper fraction to mixed number:**
$$\frac{9}{2} = 4 \frac{1}{2}$$
7. **Answer:** The team drinks $4 \frac{1}{2}$ liters of water.
**Number placement:**
- Whole number box: 4
- Fraction numerator box: 1
- Fraction denominator box: 2
Water Drunk B29074
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