Subjects arithmetic

Weight Gain 8Ed776

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1. **State the problem:** Pedro's puppy weighed $6 \frac{1}{8}$ pounds on the first visit and $9 \frac{1}{16}$ pounds on the second visit. We need to find how much weight the puppy gained between visits. 2. **Convert mixed numbers to improper fractions:** - $6 \frac{1}{8} = \frac{6 \times 8 + 1}{8} = \frac{48 + 1}{8} = \frac{49}{8}$ - $9 \frac{1}{16} = \frac{9 \times 16 + 1}{16} = \frac{144 + 1}{16} = \frac{145}{16}$ 3. **Find a common denominator to subtract:** - The denominators are 8 and 16. The least common denominator is 16. - Convert $\frac{49}{8}$ to sixteenths: $\frac{49}{8} = \frac{49 \times 2}{8 \times 2} = \frac{98}{16}$ 4. **Subtract the weights:** $$\frac{145}{16} - \frac{98}{16} = \frac{145 - 98}{16} = \frac{47}{16}$$ 5. **Convert the improper fraction back to a mixed number:** - Divide 47 by 16: $47 \div 16 = 2$ remainder $15$ - So, $\frac{47}{16} = 2 \frac{15}{16}$ 6. **Answer:** The puppy gained $2 \frac{15}{16}$ pounds between visits.