1. The problem asks to identify the law in Boolean algebra where a variable ANDed with 0 results in 0, and a variable ORed with 1 results in 1.
2. This is a fundamental property in Boolean algebra known as the Annulment Law.
3. The Annulment Law states:
- $x \cdot 0 = 0$
- $x + 1 = 1$
4. Therefore, the correct answer for question 4 is the Annulment law.
5. The second problem asks to minimize the Boolean expression $F = xyz' + xy'z + x'yz' + x'y'z + x'y'z' + xy'z$ using a 3-variable Karnaugh map.
6. Let's analyze the terms:
- $xyz'$ means $x=1, y=1, z=0$
- $xy'z$ means $x=1, y=0, z=1$
- $x'yz'$ means $x=0, y=1, z=0$
- $x'y'z$ means $x=0, y=0, z=1$
- $x'y'z'$ means $x=0, y=0, z=0$
- $xy'z$ (repeated) means $x=1, y=0, z=1$
7. Plotting these on a Karnaugh map and grouping the ones, the minimized expression is:
$$F = x'y' + y'z + yz'$$
8. This matches the first option in question 5.
9. Therefore, the correct answer for question 5 is $x'y' + y'z + yz'$.
Final answers:
- Question 4: Annulment law
- Question 5: $x'y' + y'z + yz'$
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