1. **State the problem:** We need to find the average price $\bar{p}$ of the product on the interval $40 \leq x \leq 50$ where the price function is given by $$p = \frac{132000}{490 + 4x}$$ 2. **Recall the formula for average value of a function:** The average value $\bar{f}$ of a function $f(x)$ on the interval $[a,b]$ is given by $$\bar{f} = \frac{1}{b-a} \int_a^b f(x) \, dx$$ 3. **Apply the formula to our problem:** Here, $f(x) = p = \frac{132000}{490 + 4x}$, $a=40$, and $b=50$. So, $$\bar{p} = \frac{1}{50-40} \int_{40}^{50} \frac{132000}{490 + 4x} \, dx$$ 4. **Simplify the denominator of the fraction outside the integral:** $$\bar{p} = \frac{1}{10} \int_{40}^{50} \frac{132000}{490 + 4x} \, dx$$ 5. **Final setup of the integral:** $$\boxed{\bar{p} = \frac{1}{10} \int_{40}^{50} \frac{132000}{490 + 4x} \, dx}$$ This integral expression is the exact setup to find the average price on the interval $40 \leq x \leq 50$ without factoring out any constants from the integrand.