1. **Stating the problem:** We are given the function $$y = \sqrt{(3x^2 - 1)^5}$$ and a proposed derivative $$y' = \frac{5(3x^2 - 1)^4}{2}$$. We need to evaluate if this derivative is correct. 2. **Rewrite the function:** Recall that $$\sqrt{a} = a^{\frac{1}{2}}$$, so $$y = \left((3x^2 - 1)^5\right)^{\frac{1}{2}} = (3x^2 - 1)^{\frac{5}{2}}$$. 3. **Apply the chain rule:** The derivative of $$y = (u)^{\frac{5}{2}}$$ where $$u = 3x^2 - 1$$ is $$y' = \frac{5}{2} u^{\frac{5}{2} - 1} \cdot u' = \frac{5}{2} (3x^2 - 1)^{\frac{3}{2}} \cdot (6x)$$. 4. **Calculate $$u'$$:** Since $$u = 3x^2 - 1$$, then $$u' = 6x$$. 5. **Combine all parts:** $$y' = \frac{5}{2} (3x^2 - 1)^{\frac{3}{2}} \times 6x = 15x (3x^2 - 1)^{\frac{3}{2}}$$. 6. **Compare with the given derivative:** The given derivative is $$\frac{5(3x^2 - 1)^4}{2}$$, which is missing the factor $$6x$$ from the chain rule and has an incorrect exponent. **Conclusion:** The given derivative is incorrect because the chain rule is incomplete and the exponent is wrong. **Answer:** B. Salah, aturan rantai belum lengkap