1. Problem: Use the definition of the derivative to find $f'(x)$ for $f(x) = a^x$.
2. The definition of the derivative is:
$$f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h}$$
3. Applying this to $f(x) = a^x$:
$$f'(x) = \lim_{h \to 0} \frac{a^{x+h} - a^x}{h} = \lim_{h \to 0} \frac{a^x a^h - a^x}{h} = a^x \lim_{h \to 0} \frac{a^h - 1}{h}$$
4. The limit $\lim_{h \to 0} \frac{a^h - 1}{h}$ is the definition of the derivative of $a^x$ at 0, which equals $\ln(a)$.
5. Therefore:
$$f'(x) = a^x \ln(a)$$
Final answer: $f'(x) = a^x \ln(a)$
Derivative Exponential 9Da096
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