1. The problem asks for the derivative of the function $$y = \ln(x + 3) + \ln 5$$. 2. Recall the derivative rule for natural logarithm: $$\frac{d}{dx}[\ln u] = \frac{1}{u} \cdot \frac{du}{dx}$$ where $$u$$ is a differentiable function of $$x$$. 3. Since $$\ln 5$$ is a constant (because 5 is a constant), its derivative is 0. 4. For $$\ln(x + 3)$$, let $$u = x + 3$$, so $$\frac{du}{dx} = 1$$. 5. Applying the derivative rule: $$\frac{dy}{dx} = \frac{1}{x + 3} \cdot 1 + 0 = \frac{1}{x + 3}$$. 6. Therefore, the derivative of $$y = \ln(x + 3) + \ln 5$$ is: $$\boxed{\frac{dy}{dx} = \frac{1}{x + 3}}$$