1. The problem asks us to identify which description correctly matches the increasing intervals of the function based on the graph. 2. From the graph description, the function has local maxima near $x=-3$ and $x=3$, and local minima near $x=-1$ and $x=1$. 3. The function is increasing on intervals approximately $(-3,-1)$ and $(1,3)$, and decreasing on $(-6,-3)$, $(-1,1)$, and $(3,6)$. 4. Let's analyze each option: - Option 1: "increasing before $x=0$ and after $x=3$". This means increasing on $(-\infty,0)$ and $(3,\infty)$, which is incorrect because the function decreases before 0 and after 3. - Option 2: "increasing before $x=-2$ and from $x=0$ to $x=2$". Increasing before $-2$ means on $(-\infty,-2)$, but the function decreases on $(-6,-3)$ and increases only after $-3$. Also, from 0 to 2, the function is partly decreasing and increasing, so this is incorrect. - Option 3: "increasing before $x=-3$ and from $x=0$ to $x=3$". Increasing before $-3$ means on $(-\infty,-3)$, but the function decreases there. From 0 to 3, the function increases only on $(1,3)$, so this is incorrect. - Option 4: "increasing before $x=-1$ and after $x=1$". Increasing before $-1$ means on $(-\infty,-1)$, but the function decreases on $(-6,-3)$ and increases only on $(-3,-1)$. After $1$, the function increases on $(1,3)$ but decreases on $(3,6)$. This option partially matches the increasing intervals. 5. The best match is the function is increasing on $(-3,-1)$ and $(1,3)$, which corresponds to option 4's "increasing before $x=-1$" (interpreted as increasing on $(-3,-1)$) and "after $x=1$" (interpreted as increasing on $(1,3)$). 6. Therefore, the correct description is: It is increasing before $x=-1$ and after $x=1$. Final answer: It is increasing before $x=-1$ and after $x=1$.