1. **State the problem:** We need to find the gradient (slope) of the curve defined by the function $$y = x^2 - 2x + 3$$ at the point where $$x = 2$$. 2. **Recall the formula:** The gradient of a curve at a point is given by the derivative of the function with respect to $$x$$, evaluated at that point. 3. **Find the derivative:** Differentiate $$y = x^2 - 2x + 3$$ using the power rule: $$\frac{dy}{dx} = 2x - 2$$ 4. **Evaluate the derivative at $$x=2$$:** $$\frac{dy}{dx}\bigg|_{x=2} = 2(2) - 2 = 4 - 2 = 2$$ 5. **Interpretation:** The gradient of the curve at $$x=2$$ is $$2$$, meaning the slope of the tangent line to the curve at that point is 2. **Final answer:** The gradient when $$x=2$$ is $$2$$.