1. **Problem Statement:** We analyze graph 6 to answer three questions about the function $f$:
(a) At what numbers $a$ does $\lim_{x \to a} f(x)$ not exist?
(b) At what numbers $a$ is $f$ not continuous?
(c) At what numbers $a$ does $\lim_{x \to a} f(x)$ exist but $f$ is not continuous at $a$?
2. **Understanding the graph:**
- There is a vertical asymptote near $x=1$, so the limit does not exist there.
- There is a hole on the $x$-axis near $x=3$ with a filled point above it, indicating a removable discontinuity.
- There is a rising line segment to a filled point near $x=5$ and a separate horizontal ray starting from an open circle above that point, indicating a jump discontinuity.
3. **Step (a): Limits that do not exist**
- At $x=1$, the vertical asymptote means $\lim_{x \to 1} f(x)$ does not exist.
4. **Step (b): Points where $f$ is not continuous**
- At $x=1$, due to the vertical asymptote.
- At $x=3$, because of the hole and the filled point above it.
- At $x=5$, because the function jumps from the filled point to the open circle.
5. **Step (c): Limits exist but $f$ is not continuous**
- At $x=3$, the limit exists (the function approaches the hole), but $f(3)$ is defined differently (filled point above), so discontinuous.
- At $x=5$, the limit from the left exists and equals the filled point, but the function value is different (open circle above), so discontinuous.
**Final answers:**
- (a) $x=1$
- (b) $x=1, 3, 5$
- (c) $x=3, 5$
Graph 6 Analysis 5D7B80
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