1. **State the problem:** We are given the equation of a circle: $$x^2 + y^2 = 16$$ and need to find the derivative $$\frac{dy}{dx}$$.
2. **Formula and rules:** Since $$y$$ is implicitly defined as a function of $$x$$, we use implicit differentiation. Differentiate both sides with respect to $$x$$.
3. **Differentiate each term:**
- $$\frac{d}{dx}(x^2) = 2x$$
- $$\frac{d}{dx}(y^2) = 2y \frac{dy}{dx}$$ (by chain rule)
- $$\frac{d}{dx}(16) = 0$$
4. **Write the differentiated equation:**
$$2x + 2y \frac{dy}{dx} = 0$$
5. **Solve for $$\frac{dy}{dx}$$:**
$$2y \frac{dy}{dx} = -2x$$
6. **Cancel common factor 2:**
$$\cancel{2}y \frac{dy}{dx} = -\cancel{2}x$$
7. **Isolate $$\frac{dy}{dx}$$:**
$$\frac{dy}{dx} = -\frac{x}{y}$$
**Final answer:**
$$\boxed{\frac{dy}{dx} = -\frac{x}{y}}$$
Implicit Derivative C99D13
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