1. **Problem Statement:** We need to find all values of $x$ in the open interval $(-9,9)$ where the function $f$ has an inflection point. 2. **Definition and Formula:** An inflection point occurs where the concavity of the function changes. This happens where the second derivative $f''(x)$ changes sign, which usually corresponds to points where $f''(x) = 0$ or $f''(x)$ is undefined. 3. **Given Information:** We have the graph of $f$ and the slope of the tangent line at $x = -8.9$ is $f'(-8.9) = -3.03406$. The slope values help us understand the behavior of $f'$ (the first derivative). 4. **Approach:** - Identify points where the slope of $f'$ (which is $f''$) changes sign. - These points correspond to where the graph of $f$ changes concavity (from concave up to concave down or vice versa). 5. **Using the Graph:** - Look for points where the slope of the tangent line to $f$ changes from increasing to decreasing or vice versa. - These points are typically where the curve changes from a peak to a valley or vice versa. 6. **Conclusion:** - The inflection points are the $x$-values where $f''(x)$ changes sign. - From the graph description, these points are located between peaks and valleys within $(-9,9)$. Since the exact function or $f''(x)$ is not given, the precise $x$-values of inflection points must be identified visually from the graph where the concavity changes. **Final answer:** The inflection points are all $x$ in $(-9,9)$ where the concavity of $f$ changes, i.e., where $f''(x)$ changes sign, which can be found by observing the graph's curvature changes.